Sorry, I'll try to be a bit less obtuse.
If you wire a resistor of 6.8 ohms in parallel with each of the headphone feeds, the amp will be presented with about 5.6 ohms load.
( 1/6.8) + (1/32) is approx = (1/5.6)
The resistors would need to be quite high wattage, as they will be taking most of the output of the amp, and they would need to be non-inductive too.
Being in parallel, and taking most of the load, they are a "shunt".
I had a look at the service manual here:
www.scribd.com/doc/23336802/Cambridge-Azur640A-Pwr-Sm
which is very fiddly to zoom into for sufficient detail to read, and doesn't help a lot, other than confirm it is class B and give detail of the output change-over relay which mutes the speakers when you plug the headphones in.
As a complete aside, there are some people having problems immediately after unplugging the headphones. Quite what happens to the amplifier as the output change-over relay operates is anyones guess.
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